A weak acid `HX(K_(a) = 10^(-5))` on reaction with `NaOH` gives `NaX`. For `0.1M` aqueous solution of `NaX`, the `%` hydrolysis is

Options

A. `1%`
B. `0.01%`
C. `0.001%`
D. `0.15%`

Answer

B

Explanation

Salt of `W_(A)//S_(B)` is formed
`{:(X^(Theta)+,H_(2)OhArr,HX+,overset(Theta)OH,),(1,-,0,0,),(C(1-h),,Ch,Ch,):}`
`:. H = sqrt((K_(h))/(c)) = sqrt((K_(w))/(K_(a).C))`
`= ((10^(-14))/(10^(-5)xx0.1))^(1//2) = 10^(-4)`
`% h = 10^(-4) xx 100 = 10^(-2) = 0.01`