Home
Class 11
CHEMISTRY
The hydrolysis constang of 0.1M aqueous ...

The hydrolysis constang of `0.1M` aqueous solution of sodium acetate if `K_(a)` of `CH_(3)COOH = 1.8 xx 10^(-5)` is

A

`5.5 xx 10^(-10)`

B

`4.5 xx 10^(-8)`

C

`5.5 xx 10^(-12)`

D

None of these

Text Solution

Verified by Experts

The correct Answer is:
A

`K_(h) = (K_(w))/(K_(a)) = (10^(-14))/(1.8 xx 10^(-5)) = 5.5 xx 10^(-10)`
Promotional Banner

Topper's Solved these Questions

  • IONIC EQUILIBRIUM

    CENGAGE CHEMISTRY|Exercise Ex 8.4|39 Videos
  • IONIC EQUILIBRIUM

    CENGAGE CHEMISTRY|Exercise Ex 8.5|6 Videos
  • IONIC EQUILIBRIUM

    CENGAGE CHEMISTRY|Exercise Ex 8.2|27 Videos
  • HYDROGEN, WATER AND HYDROGEN PEROXIDE

    CENGAGE CHEMISTRY|Exercise Subjective Archive (Subjective)|3 Videos
  • ISOMERISM

    CENGAGE CHEMISTRY|Exercise Assertion-Reasoning Type|1 Videos

Similar Questions

Explore conceptually related problems

Calculate the degree of hydrolysis of 0.1 M solution of sodium acetate at 298 K : K_(a) = 1.8 xx 10^(-5) .

What is the pH of an aqueous solution of ammonium acetate (K_a= K_b =1.8 xx 10^(-5))

Determine the hydrolysis constantand degree of hydrolysis of 0.01 M solution of ammonium acetate , given that K_(a) =1.752 xx 10^(-5) , K_(b) =1.74 xx 10^(-5)

Calculate the percentage hydrolysis of decinormal solution of ammonium acetate given that k_(a) = 1.75 xx 10^(-5), K_(b) =1.80 xx 10^(-5) and K_(w) = 1.0 xx 10^(-14)

What will be the hydrogen ion concentration of a solution obtained by mixing 500ml of 0.2 M acetic acid and 500ml of 0.4 M sodium acetate ? (K_(a)CH_(3)COOH)=1.8 xx 10^(-5))

Calculate the degree of hydrolysis of a decimolar solution of ammonium acetate at 25^@C . K_a(CH_3COOH)=1.75xx10^(-5), K_b(NH_4OH)=1.81xx10^(-5)

a. Calculate the percentage hydrolysis of 0.003M aqueous solution of NaOH. K_(a) for HOCN = 3.3 xx 10^(-4) . b. What is the pH and [overset(Theta)OH] of 0.02M aqueous solution of sodium butyrate. (K_(a) = 2.0 xx 10^(-5)) .

CENGAGE CHEMISTRY-IONIC EQUILIBRIUM-Ex 8.3
  1. The pH of blood is 7,4. If the buffer in blood constitute CO(2) and HC...

    Text Solution

    |

  2. The pH of blood is

    Text Solution

    |

  3. Buffer in blood consists of

    Text Solution

    |

  4. K(a) for HCN is 5 xx 10^^(-10) at 25^(@)C. For maintaining a constant ...

    Text Solution

    |

  5. 18mL of mixture of CH(3)COOH and CH(3)COONa required 6mL of 0.1M NaOH ...

    Text Solution

    |

  6. The pH of blood is maintained by the balance between H(2)CO(3) and NaH...

    Text Solution

    |

  7. Fixed volume of 0.1M benzoic acid (pK(a) = 4.2) solution is added into...

    Text Solution

    |

  8. 0.1mol of RNH(2)(K(b) = 5 xx 10^(-5)) is mixed with 0.08mol of HC1 and...

    Text Solution

    |

  9. A weak acid HX(K(a) = 10^(-5)) on reaction with NaOH gives NaX. For 0....

    Text Solution

    |

  10. The pH of 0.1M solution of the following salts decreases in the order

    Text Solution

    |

  11. The degree of hydrolysis of a salt of W(A) and W(B) in its 0.1M soluti...

    Text Solution

    |

  12. pH of separate solution of four potassium salts, KW,KX, KY and KZ are ...

    Text Solution

    |

  13. Which of the following solutions have pH lt 7.

    Text Solution

    |

  14. Which of the following solution have pH gt 7. I. BaF(2) II. RbI I...

    Text Solution

    |

  15. The expression to calculate pH of sodium acetate solution at 25^(@)C i...

    Text Solution

    |

  16. The correct order of increasing [H(3)O^(o+)] in the following aqueous ...

    Text Solution

    |

  17. pH of water is 7. When a substance Y is dissolved in water, the pH bec...

    Text Solution

    |

  18. The hydrolysis constang of 0.1M aqueous solution of sodium acetate if ...

    Text Solution

    |

  19. The compound whose 0.1M solution is basic is

    Text Solution

    |

  20. K(a) for ascorbic acid (HASc) is 5 xx 10^(-5). Calculate the [H^(o+)] ...

    Text Solution

    |