The `K_(sp)` of `AgC1` at `25^(@)C` is `1.6 xx 10^(-9)`, find the solubility of salt in `gL^(-1)` in water.

Answer

A, C, D

Explanation

`{:(AgC1rarr,Ag^(o+)+,C1^(Theta),,),(,S,S,,):}`
`K_(sp) = S^(2)`
`S = sqrt(K_(sp)) = (1.6 xx 10^(-9))^((1)/(2))`
`= (16 xx 10^(-10))^((1)/(2)) = 4 xx 10^(-5)M`
`("Mw of" AgC1 = 143.5)`
Thus, `S = 4 xx 10^(-5) xx 143.5 = 5.74 xx 10^(-3) gL^(-1)`