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If solutbility of Ca(IO(3))(2) in water ...

If solutbility of `Ca(IO_(3))_(2)` in water at `20^(@)C` is `3.9gL^(-1)`. Calculate the `K_(sp)`. Given `Mw Ca(IO_(3))_(2) = 390`.

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The correct Answer is:
A, C, D
`M = (3.9)/(390) = 0.01M = S`
`{:(Ca (IO_(3))_(2) hArr,Ca^(2+)+,2IO_(3)^(Theta),,),(,S,2S,,):}`
`K_(sp) = 4S^(3) = 4 xx (0.01)^(3) = 4 xx 10^(-6) M^(3)`
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CENGAGE CHEMISTRY-IONIC EQUILIBRIUM-Ex 8.4
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