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The solubility of A(2)B(3) is "x mol dm"...

The solubility of `A_(2)B_(3)` is "x mol dm"^(-3)`. Its `K_(sp)` is

A

`6x^(4)`

B

`64x^(4)`

C

`36x^(5)`

D

`108x^(5)`

Text Solution

Verified by Experts

The correct Answer is:
D
`K_(sp) = (2)^(2).(3)^(2).x^(2+3) = 108 x^(5)`
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