Home
Class 11
CHEMISTRY
The degree of dissociation of weak elect...

The degree of dissociation of weak electrolyde is inversely proportional to the square root fo concentration. It is called Ostwald's dilution law.
`alpha = sqrt((K_(a))/(c))` As the tempertaure increases, degree of dissociation will increase.
`(alpha_(1))/(alpha_(2)) = sqrt((K_(a_(1)))/(K_(a_(2))))` if concentration is same.
`(alpha_(1))/(alpha_(2)) = sqrt((c_(2))/(c_(1)))` if acid is same.
`0.01M CH_(3)COOH` has `4.24%` degree of dissociation, the degree of dissociation of `0.1M CH_(3)COOH` will be

A

`1.33%`

B

`4.24%`

C

`5.24%`

D

`0.33%`

Text Solution

Verified by Experts

The correct Answer is:
A

Use: `(alpha_(1))/(alpha_(2)) = sqrt((C_(2))/(C_(1))) rArr (4.24)/(alpha_(2)) = sqrt((0.1)/(0.01))`
`rArr alpha_(2) =(4.24)/(sqrt(10)) % = 1.33 %`
Promotional Banner

Topper's Solved these Questions

  • IONIC EQUILIBRIUM

    CENGAGE CHEMISTRY|Exercise Exercises Multiple Correct|33 Videos
  • IONIC EQUILIBRIUM

    CENGAGE CHEMISTRY|Exercise Exercises Single Correct|121 Videos
  • IONIC EQUILIBRIUM

    CENGAGE CHEMISTRY|Exercise Exercises Subjective(Coordination Equilibria)|2 Videos
  • HYDROGEN, WATER AND HYDROGEN PEROXIDE

    CENGAGE CHEMISTRY|Exercise Subjective Archive (Subjective)|3 Videos
  • ISOMERISM

    CENGAGE CHEMISTRY|Exercise Assertion-Reasoning Type|1 Videos

Similar Questions

Explore conceptually related problems

The degree of dissociation of weak electrolyde is inversely proportional to the square root fo concentration. It is called Ostwald's dilution law. alpha = sqrt((K_(a))/(c)) As the tempertaure increases, degree of dissociation will increase. (alpha_(1))/(alpha_(2)) = sqrt((K_(a_(1)))/(K_(a_(2)))) if concentration is same. (alpha_(1))/(alpha_(2)) = sqrt((c_(2))/(c_(1))) if acid is same. pH of 0.005 M HCOOH [K_(a) = 2 xx 10^(-4)] is equal to

The degree of dissociation of weak electrolyde is inversely proportional to the square root fo concentration. It is called Ostwald's dilution law. alpha = sqrt((K_(a))/(c)) As the tempertaure increases, degree of dissociation will increase. (alpha_(1))/(alpha_(2)) = sqrt((K_(a_(1)))/(K_(a_(2)))) if concentration is same. (alpha_(1))/(alpha_(2)) = sqrt((c_(2))/(c_(1))) if acid is same. a_(1) and a_(2) are in ratio of 1:2, K_(a_(1)) = 2xx10^(-4) . What will be K_(a_(2)) ?

The degree of dissociation of 0.1N CH_(3)COOH is (K_(a)= 1xx10^(-5))

The degree of dissociation of a weak monoprotic acid of concentration 1.2xx10^(-3)"M having "K_(a)=1.0xx10^(-4 is

If degree of dissociation of 2M CH_3 COOH is 10% then degree of dissociation of this acetic acid in 3 Molar CH_3 COONa solution will be

The degree of dissociation (alpha) of a weak electrolyte, A_(2)SO_(4) is related to Vant Hoff factor (i) by the expression

CENGAGE CHEMISTRY-IONIC EQUILIBRIUM-Exercises Linked Comprehension
  1. In equalitative analysis, cations of graph II as well as group IV both...

    Text Solution

    |

  2. In equalitative analysis, cations of graph II as well as group IV both...

    Text Solution

    |

  3. The degree of dissociation of weak electrolyde is inversely proportion...

    Text Solution

    |

  4. The degree of dissociation of weak electrolyde is inversely proportion...

    Text Solution

    |

  5. The degree of dissociation of weak electrolyde is inversely proportion...

    Text Solution

    |

  6. The following solutions are mixed: 500mL of 0.01 M AgNO(3) and 500mL s...

    Text Solution

    |

  7. The following solutions are mixed: 500mL of 0.01 M AgNO(3) and 500mL s...

    Text Solution

    |

  8. The following solutions are mixed: 500mL of 0.01 M AgNO(3) and 500mL s...

    Text Solution

    |

  9. When 1.5mol of CuCI(2).2H(2)O is dissolved in enough water to make 1.0...

    Text Solution

    |

  10. When 1.5mol of CuCI(2).2H(2)O is dissolved in enough water to make 1.0...

    Text Solution

    |

  11. When 1.5mol of CuCI(2).2H(2)O is dissolved in enough water to make 1.0...

    Text Solution

    |

  12. Acid rain takes place dur to combination of acidic oxides with water a...

    Text Solution

    |

  13. Acid rain takes place dur to combination of acidic oxides with water a...

    Text Solution

    |

  14. In atmosphere, SO(2) and NO are oxidised to SO(3) and NO(2), respectiv...

    Text Solution

    |

  15. In atmosphere, SO(2) and NO are oxidised to SO(3) and NO(2), respectiv...

    Text Solution

    |

  16. In atmosphere, SO(2) and NO are oxidised to SO(3) and NO(2), respectiv...

    Text Solution

    |

  17. In atmosphere, SO(2) and NO are oxidised to SO(3) and NO(2), respectiv...

    Text Solution

    |

  18. In acid-base titration react rapidly to neutralise each other. Equival...

    Text Solution

    |

  19. In acid-base titration react rapidly to neutralise each other. Equival...

    Text Solution

    |

  20. In acid-base titration react rapidly to neutralise each other. Equival...

    Text Solution

    |