Aqueous solutions of `Na_(2)C_(2)O_(4)` and `CaCI_(2)` are mixed and precipitate of `CaC_(2)O_(4)` formed is filered and dried. `250 mL` of the saturated solution of `CaC_(2)O_(4)` required `6.0 mL` of `0.001M KMnO_(4)` solution in acidic medium for complete titration.
Equivalent of `KMNO_(4)` required in the titration and equivalent of `C_(2)O_(4)^(2-)` ion present in `CaC_(2)O_(4)`, respectively, are

Options

A. `3xx10^(-5),3xx10^(-5)`
B. `1.8xx10^(-5),3xx10^(-6)`
C. `3xx10^(-6),6xx10^(-6)`
D. `6xx10^(-6),3xx10^(-6)`

Answer

A

Explanation

i. `5e^(-) + MnO_(4)^(Theta) rarr Mn^(2+) ('n' "factor" = 5)`
Equivalent of `MnO_(4)^(Theta)`
`= 5 xx 6 xx 10^(-6) = 3 xx 10^(-5)`
ii. `C_(2)O_(4)^(2-) rarr 2CO_(2) + 2e^(-) ('n' "factor" = 2)`
Equivalent of `C_(2)O_(4)^(Theta) = 2 xx 1.5 xx 10^(-5)`
`= 3 xx 10^(-5)`