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A solution of 0.1M NaZ has pH = 8.90. Th...

A solution of `0.1M NaZ` has `pH = 8.90`. The `K_(a)` of `HZ` is

A

`6.3 xx 10^(-11)`

B

`6.3 xx 10^(-10)`

C

`1.6 xx 10^(-5)`

D

`1.6 xx 10^(-6)`

Text Solution

Verified by Experts

The correct Answer is:
C
`NaZ` is salt of `W_(A)//S_(B)`
`:. pH = (1)/(2) (pK_(w) +pK_(a) + logC)`
`8.9 xx2 = 14 + pK_(a) + log 0.1`
`17.8 = 14 + pK_(a) - 1`
`pK_(a) = 4.8`,
`K_(a) = "Antilog" (-4.8) = "Antilog" (-4-0.8 +1-1)`
`= "Antilog" (bar(5).2) = 1.585 xx 10^(-5) ~~ 1.6 xx 10^(-5)`.
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