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If K(sp) (PbSO(4)) =1.8 xx 10^(-8) and K...

If `K_(sp) (PbSO_(4)) =1.8 xx 10^(-8)` and `K_(a) (HSO_(4)^(Theta)) = 1.0 xx 10^(-2)` the equilibrium constant for the reaction.
`PbSO_(4)(s) +H^(o+)(aq) hArr HSO_(4)^(Theta)(aq) +Pb^(2+)(aq)` is

A

`1.8 xx 10^(-6)`

B

`1.8 xx 10^(-10)`

C

`2.8 xx 10^(-10)`

D

`1.0 xx 10^(-2)`

Text Solution

Verified by Experts

The correct Answer is:
A
`PbSO_(4)(s) hArr Pb^(+2)(aq) +SO_(4)^(2-)(aq) (K_(sp)) ….(i)`
`HSO_(4)^(Theta)(s) hArr H^(o+) (aq) +SO_(4)^(2-)(aq) (K_(a)) …(ii)`
Subtracting equation (ii) from (i), then
`PbSO_(4) +H^(o+)(aq) hArr Pb^(2+) (aq) +HSO_(4)^(Theta)(aq) (K_(eq))`
`:. K_(eq) = (K_(sp))/(K_(a)) = (1.8 xx 10^(-8))/(1.0 xx 10^(-2)) = 1.8 xx 10^(-6)`
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