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The solubility products of MA, MB, MC an...

The solubility products of `MA, MB, MC` and MD are `1.8xx10^(-10), 4xx10^(-3), 4xx10^(-8)` and `6xx10^(-5)` respectively. If a `0.01M` solution of MX is added dropwise to a mixture containing `A^(-), B^(-), C^(-)` and `D^(-)` ions, then the one to be precipitated first will be:

A

`MA`

B

`MB`

C

`MC`

D

`MD`

Text Solution

Verified by Experts

The correct Answer is:
A
Since all compound `(MA, MB, MC`, and `MD)` are uni-univalent type. All will have the same formula of solubility in `H_(2)O` (i.e., `sqrt(K_(sp)))`. Same concentration of common ion `(M^(o+))` is added, so solubilities of all will be supressed.
Hence, the compound with least `K_(sp)` value will be precipitated, i.e., `MA` with `K_(sp) = 1.8 xx 10^(-10)`.
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