The `pH` of a solution `7.00`. To this solution, sufficient base is added to increase the `pH` to `12.0`. The increase in `overset(Theta)OH` ion concentration is

Options

A. `5 times`
B. `100 times`
C. `10^(5)times`
D. `4 times`

Answer

C

Explanation

Initial `pH` or `pOH = 7, :. [overset(Theta)OH] = 10^(-7)M`.
Final `pH = 12, :. pOH = 2, [overset(Theta)OH] = 10^(-2)M`.
Increase in `[overset(Theta)OH] = (10^(-2))/(10^(-7)) = 10^(5)` times