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Assuming H(2)SO(4) to be completely ioni...

Assuming `H_(2)SO_(4)` to be completely ionised the `pH` of a `0.05M` aqueous of sulphuric acid is approximately

A

`0.01`

B

`0.005`

C

`2`

D

`1`

Text Solution

Verified by Experts

The correct Answer is:
D
`0.05 M_(H_(2)SO_(4)) = 2xx0.05 N_(H_(2)SO_(4)) = 0.1N`
`:. [H_(3)O^(o+)] = [0.1] = 10^(-1)`
`-log [H_(3)O^(o+)] =- log [10^(-1)] = 1`
`pH = 1`
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