Solubility of salt `A_(2)B_(3)` is `1 xx 10^(-4)`, its solubility product is

Options

A. `1.08 xx 10^(20)`
B. `1.08 xx 10^(18)`
C. `2.6 xx 10^(-18)`
D. `1.08 xx 10^(-18)`

Answer

D

Explanation

`{:(A_(2)B_(3)hArr,2A^(3+)+,3B^(2-),),(,2S,3S,):}`
`K_(sp) = (2S)^(2) (3S)^(2) = 108 S^(5) = 108 xx (10^(-4))^(5)`
`= 108 xx 10^(-20) = 1.08 xx 10^(-20) = 1.08 xx 10^(-18)`.