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At 90^(@)C, pure water has [H(3)O^(o+)] ...

At `90^(@)C`, pure water has `[H_(3)O^(o+)] = 10^(-6.7)mol L^(-1)`. What is the value of `K_(w)`at `90^(@)C`?

A

`10^(-6)`

B

`10^(-12)`

C

`10^(-13.4)`

D

`10^(-6.7)`

Text Solution

Verified by Experts

The correct Answer is:
C
`K_(w) = [H_(3)O^(o+)][overset(Theta)OH]`
`=10^(-6.7) xx 10^(-6.7) = 10^(-13.4)`
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