The `pH` of a solution is `5.00`. To this solution, sufficient acid is added to lower the `pH` to `2.00`. The corresponding increase in `H_(3)O^(o+)` ion concentration is

Options

A. `1000` times
B. `2.5` times
C. `100` times
D. `5` times

Answer

A

Explanation

`pH = 5.0, pOH = 11`.
`pH_(1) = 5.0, [H_(3)O^(o+)] = 10^(-5)m`.
New `pH_(2) = 2.0, [H_(3)O^(o+)] = 10^(-2)M`.
Increase in concentration of `[H_(3)O^(o+)]`
`= (10^(-2))/(10^(-5)) = 10^(3) = 1000` times