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If the dissociation constant of NH(4)OH ...

If the dissociation constant of `NH_(4)OH` is `1.8 xx 10^(-5)`, the concentration of `overset(Theta)OH` ions, in `mol^(-1) of 0.1 M NH_(4)OH` is

A

`1.8 xx 10^(-6)`

B

`1.34 xx 10^(-3)`

C

`4.20 xx 10^(-2)`

D

`5.0 xx 10^(-2)`

Text Solution

Verified by Experts

The correct Answer is:
B
`NH_(4)OH` is `W_(B)`
`:. [overset(Theta)OH] = Calpha = sqrt(K_(b)xxc) = sqrt(1.8 xx 10^(-5) xx 0.1)`
`=1.34 xx 10^(-3)M`
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