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When 0.002mol of acid is added to 250 mL...

When `0.002mol` of acid is added to `250 mL` of a buffer solution, `pH` decreases by `0.02`units. The buffer capacity of the system is

A

`0.1`

B

`0.2`

C

`0.3`

D

`0.4`

Text Solution

Verified by Experts

The correct Answer is:
D
Buffer capacity
`= ("Number of moles per litre of acid or base added")/("Change in pH or pOH")`
`["Acid"] = (0.002 xx 1000)/(250) = 0.008M`
Buffer capacity `= (0.008)/(0.02) = 0.4`
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