A solution contains `10mL` of `0.1N NaOH` and `10mL` of `0.05Na_(2)SO_(4), pH` of this solution is

Options

A. `7`
B. Less than `7`
C. Greater than `7`
D. Zero

Answer

C

Explanation

`NaOH = 10 xx 0.1 = 1 mEq`
`Na_(2)SO_(4) = 10 xx 0.05 = 0.5 mEq`
But `pH` of solution id due to only strong base, `NaOH` and will be greater than `7`. Salt of `S_(A)//S_(B)`, has no effect on `pH`, since its `pH` is `7`.