If the diameter of a carbon atom is `0.15 nm`, calculate the number of carbon atom which can be placed side by side in a straight line length of scale of length `20 cm` long.

Explanation

Diameter of carbon atom `=0.15 nm`
`=0.15xx10^(-9) m=1.5xx10^(-10) m`
Length along which atoms are to be placed `=20 cm`
`=20xx10^(-2) m=2xx10^(-1)m`
:. Number of C atoms which can be placed along the length
`=(2xx10^(-1))/(1.5xx10^(-10))=1.33xx10^(9)`