The diameyer of zinc atom is `2.6 A`. Calculate (a) radius of zinc atom in pm and (b) number of atoms present in a length of `1.6 cm` if the zinc atoms are arranged side by side lengthwise.

Explanation

a. Radius `=(2.6 Å)/2=1.3xx10^(-10)m=130xx10^(-12)m`
`=130 p m`
b. Given length `=1.6 cm=1.6xx10^(-2)m`
Diameter of one atom `=2.6Å=2.6xx10^(-10)m`
`:.` Number of atoms present along the length
`=(1.6xx10^(-2))/(2.6xx10^(-10))=6.154xx10^(7)`