The velocity associated with a proton moving in a potential difference of `1000 V` is `4.37xx10^(5) m s^(-1)`. If the hockey ball of mass `0.1 kg` is moving with this velocity, calculate the wavelength associated with this velocity.

Explanation

`lambda=h/(mv)=(6.626xx10^(-34) kgm^(2) s^(-1))/((0.1 kg)xx(4.37xx10^(5) m s^(-1)))`
`=1.516xx10^(-28) m`