At `0^(@)C` the density of a gaseous oxide at 2 bar is same as that of nitrogen at 5 bar What is the molecular mass of the oxide ? .

Explanation

Density of nitrogen, `rho=(Pm)/(RT)`
`P=5xx0.987 atm, m=28`
`:. rho=(5xx0.987xx28)/(0.0821xx273)`
Density of gaseous oxide
`(5xx0.987xx28)/(0.0821xx273)=(5xx0.987xx x)/(0.0821xx273)`
or `x=(5xx28)/2=70 g mol^(-1)`