Calculate the temperature of `4.0 mol` of a gas occupying `5 dm^(3)` at 3.32 bar.
Strategy : List the variables with the proper units. Then solve the ideal gas equation for `T` by substituting the values.

Explanation

`PV=nRT`
`P=3.32 "bar", V=5 dm^(3)`
`n=4 mol`,
`R=0.083 "bar" dm^(3) K^(-1) mol^(-1)`
Therefore
`3.32xx5=4xx0.083xxT`
or `T=(3.32xx5)/(4xx0.083)=50 K`