For the following equilibrium, `K_(c )=6.3xx10^(14) at 1000 K`
`NO(g)+O_(3)(g) hArr NO_(2)(g)+O_(2)(g)`
Both the forward and reverse reactions in the equilibrium are elementary bimolecular reactions. What is `K_(c )`, for the reverse reaction?

Explanation

To find the equilibrium constant \( K_c \) for the reverse reaction of the given equilibrium:

1. **Write the given equilibrium reaction**:
\[ \text{NO(g)} + \text{O}_3(g) \rightleftharpoons \text{NO}_2(g) + \text{O}_2(g) \]

2. **Identify the equilibrium constant for the forward reaction**:
...