At `450 K, K_(p)=2.0xx10^(10)//` bar for the given reaction at equilibrium.
`2SO_(2)(g)+O_(2)(g) hArr 2SO_(3)(g)`
What is `K_(c )` at this temperature?

Explanation

For the given reaction, `Deltan_(g)=2-3=-1`
`K_(p)=K_(c )(RT)^(Deltan) or K_(c )=K_(p)(RT)^(-Deltan)=K_(p)(RT)`
`=(2.0xx10^(10) "bar"^(-1))(0.0831 L "bar" K^(-1) mol^(-1))(450 K)`
`=74.8xx10^(10)L mol^(-1)=7.48xx10^(11) L mol^(-1)`