What is the equilibrium concentration of each of the substance in the euilibrium when the initial concentration of `Icl` was `0.78 M`?
`2ICl(g) hArr I_(2)(g)+Cl_(2)(g), K_(c)=0.14`

Explanation

To find the equilibrium concentrations of ICl, I2, and Cl2 in the reaction:

\[ 2 \text{ICl}(g) \rightleftharpoons \text{I}_2(g) + \text{Cl}_2(g) \]

with an initial concentration of ICl as 0.78 M and \( K_c = 0.14 \), we will follow these steps:

### Step 1: Set up the initial concentrations
- Initial concentration of ICl = 0.78 M
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