The value of `K_(c )` for the reaction `3O_(2)(g) hArr 2O_(3)(g)` is `2.0xx10^(-50)` at `25^(@)C`. If the equilibrium aoncentration of `O_(2)` in air at `25^(@)C` is `1.6xx10^(-2)`, what is the concentration of `O_(3)`?

Explanation

`K_(c )=([O_(3)]^(2))/([O_(2)]^(3)):. 2.0xx10^(-50)=([O_(3)]^(2))/((1.6xx10^(-2))^(2))`
or `[O_(3)]^(2)=(2.0xx10^(-50))(1.6xx10^(-2))^(3)=8.192xx10^(-56)`
or `[O_(3)]=2.86xx10^(-28) M`