The degree of ionisation of a `0.1 M` bromoacetic acid solution is `0.13`. Calculate the `pH` of the solution and the `pK_(a)` of bromoacetic acid.

Explanation

`{:(,BrCH_(2)COOH,hArr,CH_(2)(Br)COO^(Θ),+,H^(o+)),("Initial conc.",C,,0,,0),("Conc. at Eq.",C-Calpha,,Calpha,,Calpha):}`
`{:(Initial conc.,C,,0,0),(Conc. at Eq.,C-Calpha,,Calpha,Calpha):}`
`K_(a)=(Calpha.Calpha)/(C(1-alpha))=(Calpha^(2))/(1-alpha)~~Calpha^(2)`
`=0.1xx(0.132)^(2)=1.74xx10^(-3)`
`pK_(a)=-log(1.74xx10^(-3))=3-0.2405=2.76`
`[H^(o+)]=Calpha=0.1xx0.132=1.32xx10^(-2)M`
`pH=-log(1//32xx10^(-2))=2-0.1206=1.88`