The ionization constant of propanoic acid is `1.32xx10^(-5)`. Calculate the degree of ionization of the acid in its `0.05 M` solution and also its `pH`. What will be its degree of ionization if the solution is `0.01 M` on `HCl` also?

Explanation

To solve the problem, we will follow these steps:

### Step 1: Write the ionization reaction and expression for the ionization constant (Ka)
The ionization of propanoic acid (CH₃CH₂COOH) can be represented as:
\[ \text{CH}_3\text{CH}_2\text{COOH} \rightleftharpoons \text{CH}_3\text{CH}_2\text{COO}^- + \text{H}^+ \]

The expression for the ionization constant (Ka) is given by:
\[ K_a = \frac{[\text{CH}_3\text{CH}_2\text{COO}^-][\text{H}^+]}{[\text{CH}_3\text{CH}_2\text{COOH}]} \]
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