The solubility product constant of `Ag_(2)CrO_(4)` and `AgBr` are `1.1xx10^(-12)` and `5.0xx10^(-13)` respectively. Calculate the ratio of the molarities of their saturated solutions.

Explanation

To calculate the ratio of the molarities of the saturated solutions of `Ag_(2)CrO_(4)` and `AgBr`, we will use the solubility product constant (Ksp) for each salt.

### Step 1: Write the dissociation equations

1. For `Ag_(2)CrO_(4)`:
\[ Ag_{2}CrO_{4} (s) \rightleftharpoons 2Ag^{+} (aq) + CrO_{4}^{2-} (aq) \]
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