The standard potential of a cell using the reaction is `1.12`. The heat of the reaction is `-504.2kJ mol ^(-1)` at `25^(@)C`. Calculate the entropy change.

Explanation

`2Ni(s)+4H_(2)Orarr 2Ni(OH)_(2)+4H^(o+)+4e^(-)`
`4H^(o+)+O_(2)+4e^(-)rarr2H_(2)O`
`DeltaG^(c-)=-nFE^(c-)=-4xx96500xx1.12=-432320J`
`DeltaG^(c-)=DeltaH^(c-)-TDeltaS^(c-)`
`:. DeltaS^(c-)=(DeltaH^(c-)-DeltaG^(c-))/(T)`
`=-(504.2xx10^(3)J-(-432320))/(298)`
`=-241.2JK^(-1)mol^(-1)`