The `EMF` of a galvanic cell composed of two hydrogen electrodes is `177 mV`. If the solution at one of the electrode has `[H^(o+)]=10^(-3)`, find the `[H^(o+)]` at the other electrode.

Explanation

`H_(2)|H^(o+)(10^(-3))|H_(2)^(o+)(x)|H_(2)`
`E=-0.059(pH_(1)-pH_(2))=-0.059(3-pH_(2))`
`177xx10^(-3)V=-0.177+pH_(2)xx0.059`
`pH_(2)=(0.354)/(0.059)=6`
`[H^(o+)]=10^(-6)M`