A hydrogen electrode placed in a buffer solution of sodium cyanide and `HCN` in the ration of `x:y` and `Y:x` has electrode potential value `a` and `b` volts, respectively, at `25^(@)C`. If the difference `a-b=35.52mV, ` what is the ratio of `y:x.`

Explanation

Acidic buffer `(NaCN+HCN)`
`pH=pK_(a)+log [(Sal t)/(Aci d)]`

`E_(1)=a=-0.059pH_(1),E_(2)=b=-0.059pH_(2)`
`a-b=-0.059pH_(1)+0.059pH_(2)`
`=0.059(pH_(1)-pH_(2))`
`35.52xx10^(-3)V=0.059(pK_(a)+log .(y)/(x)-pK_(a)-log .(x)/(y))`
`(35.52 xx 10^(-3))/(0.059)=log .(y)/(x)+log.(y)/(x)`
`0.6=2log .(y)/(x)`
`log.(y)/(x)=0.3implies(y)/(x)=2`