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Calculate Delta(r)G^(c-) of the reaction...

Calculate `Delta_(r)G^(c-)` of the reaction `:`
`Ag^(o+)(aq)+Cl^(c-)(aq) rarr AgCl(s)`
Given `:Delta_(f)G^(c-)._(AgCl)=-109kJ mol ^(-1)`
`Delta_(f)G^(c-)_((Cl^(c-)))=-129k J mol ^(-1)`
`Delta_(f)G^(c-)._((Ag^(o+)))=-77 kJ mol ^(-1)`

A

`-97 kJ mol^(-1)`

B

`-57kJ mol^(-1)`

C

`57kJmol^(-1)`

D

`97kJ mol^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
b
`Ag^(o+)(aq)+Cl^(c-)(aq)rarr AgCl(s)`
`Delta_(r)G^(c-)=Delta_(f)G^(c-)._((AgCl))-Delta_(f)G^(c-)._((Ag^(o+)))-Delta_(v)G^(c-)._((Cl^(c-)))`
`=-109-77-(-129)=-57kJ mol^(-1)`
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