A conductivity cell is used to measure the conductance of electrolyte . It makes use of conductivity of water which does not contain any ions. The cell constant of conductivity cell is determined.
If the cell constant is `0.40 cm^(-1)`, the conductivity of `0.051 M NaCl` solution having `R=1850 ohm` is equal to

Options

A. `1.08xx10^(-4)S cm^(-1)`
B. `4.32 xx 10^(-4) S cm^(-1)`
C. `2.16xx10^(-4) S cm^(-1)`
D. `5.04xx10^(-5) S cm^(-1)`

Answer

c

Explanation

Use `:k=GxxG^(**)=(0.4)/(1850)=2.16xx10^(-4)S cm^(-1)`