If `X` is the specific resistance of the solution and `N` is the normality of the solution, the equivalent conductivity of the solution is given by

Options

A. `(1000x)/(N)`
B. `(1000)/(Nx)`
C. `(1000N)/(x)`
D. `(Nx)/(1000)`

Answer

b

Explanation

Specific resistance `=x`
`:. `Specific conductance `(` or conductivity `0=k=(1)/(x)`
`:. Wedge_(eq)=(kxx1000)/(N)=(1000)/(xN)`