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The values of wedge(m)^(oo) forNH(4)Cl,N...

The values of `wedge_(m)^(oo)` for`NH_(4)Cl,NaOH,` and `NaCl` are, respectively, `149.74,248.1`,and `126.4 ohm^(-1)cm^(2)eq^(-1)`. The value of `wedge_(eq)^(oo)NH_(4)OH` is

A

`371.44`

B

`271.44`

C

`71.44`

D

It cannot be calculated from the data given.

Text Solution

Verified by Experts

The correct Answer is:
b
`wedge^(@)._(eq)`or `wedge^(@)._((NH_(4)OH))=wedge^(oo)._(eq(NH_(4)Cl))+wedge^(oo)._(eq(NaOH))-wedge^(oo)._(eq(NaCl))`
`=(149.74+248.1-126.4)`
`=271.44ohm^(-1)cm^(2)eq^(-1)`
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