If the solution of the `CuSO_(4)` in which copper rod is immersed is diluted to 10 times, the electrode potential :

Options

A. Increases by `30mV`
B. Decreases by `30mV`
C. Increases by `59mV`
D. Decrease by `59mV`

Answer

b

Explanation

`(E_(Cu^(2+)|Cu))._(1)=E^(c)._(Cu^(2+)|Cu)+(0.059)/(2)log[Cu^(2+)]`
`[Cu^(2+)(aq)+2e^(-)rarrCu(s)]`
and `(E_(Cu^(2+)|Cu))_(2)=E^(c-)._(Cu^(2+)|Cu)+(0.059)/(2)log[Cu^(2+)]_(2)`
`implies DeltaE_(Cu^(2+)|Cu)=-(0.059)/(2)V`