The standard electrode of a metal ion `(Ag|Ag^(o+))` and metal `-` insoluble salt anion `(Ag|AgCl|Cl^(c-))` are related as

Options

A. `E^(c-)._(Ag^(o+)|Ag)=E^(c-)._(Cl^(c-)|AgCl|Ag)+(RT)/(F)ln K_(sp)`
B. `E^(c-)._(Cl^(c-)|AgCl|Ag)=E^(c-)._(Ag^(o+)\Ag)+(RT)/(F)lnK_(sp)`
C. `E^(c-)._(Ag^(o+)|Ag)=E^(c-)._(Cl^(c-)|AgCl|Ag)+(RT)/(F)ln.([Cl^(c-)])/(K_(sp))`
D. `E^(c-)._(Cl^(c-)|AgCl|Ag)=E^(c-)._(Ag^(o+)|Ag)+(RT)/(F)ln.(K_(sp))/([Cl^(c-)])`

Answer

b

Explanation

When `E_(cell)=0impliesQ_(cell)=K_(sp)`
and `E^(c-)._(cell)=E^(c-)._(Ag|AgCl|Cl^(c-))-E^(c-)._(Ag^(o+)|Ag)`
`0=E^(c-)._(cell)-(RT)/(F) lnK_(sp).`
Substitute the value of `E^(c-)._(cell)` in `Eq. (i)` to get answer as in `(b)`.