The standard reduction potential at `25^(@)C` for the reaction,
volt. The equilibrium constant for the reaction `:`
is

Options

A. `10^(-12)`
B. `10^(-14)`
C. `10^(-11)`
D. `10^(-11)`

Answer

b

Explanation

Anode`: H_(2)implies2H^(o+)+2e^(-)," "E^(c-)=0V`
Cathode`: 2H_(2)O+2e^(-) rarr H_(2)+2overset(c-)(O)H,E^(c-)=-0.8277V`
`2H_(2)OhArr2H^(o+)2overset(Θ)(O)H`
Use `:=(E^(c-)._(cell)xxn_(cell))/(0.059)=logK_(w)`