When electricity is passed through a solution of `AlCl_(3)` and `13.5g` of `Al` is deposited, the number of `Faraday of electricity passed must be `………………….F`.

Options

A. `0.5`
B. `1.0`
C. `1.5`
D. `2.0`

Answer

c

Explanation

`Al^(3+)+3e^(-)rarr Al`
`1 mol of Al =27g =3F`
`:. 13.5g of Al=(3)/(27)xx13.5-=1.5F`.