The volume of gases evolved at `STP` by passing `0.1A` of current for `965g`, through an aqueous solution of potassium acetate

Options

A. `22.4mL`
B. `11.2mL`
C. `89.6mL`
D. `44.8mL`

Answer

d

Explanation

`CH_(3)COOK rarr CH_(3)OO^(c-)+K^(o+)`
At cathode, `H_(2)O` undergoes reduction of give `H_(2)`.
`H_(2)O+2e^(-) rarr 2overset(c-)(O)H+H_(2)`
`2F-=1 mol of H_(2)`
At anode,
`2CH_(3)COO^(e)rarrunderset(underset(CH_(3)-CH_(3)+2CO_(2))(darr))(2CHOO^(*)+2e^(-))`
`2F-=1 mol of C_(2)H_(6)` and `2 mol of CO_(2)`
Total volume at cathode and anode
`=4 mol =4xx22.4L`
`2F=2xx96500Cimplies4xx22.4L`
`0.1xx965Cimplies(4xx22.4xx0.1xx965)/(2xx96500)`
`implies0.0448L=44.8 mL`