The `EMF` of concentration cell consisting of two zinc electrodes, one dipping into `M//4` solution of `ZnSO_(4)` and the other into `M//16` solution of the same salt at `25^(@)C` is

Options

A. `0.0125V`
B. `0.0250V`
C. `0.0178V`
D. `0.0356V`

Answer

c

Explanation

For concentration cell, `E^(c-)=0`
`Zn|underset(Low conc)(Zn^(2+)(M//16))||underset(High conc)(Zn^(+2)(M//4))|Zn`
`E=-(0.059)/(2)log.((Zn^(2+))_(a))/((Zn^(2+))_(c))`
`=-(0.059)/(2) log .(M//16)/(M//4)`
`=-(0.059)/(2)log.((1)/(4))`
Solve,` E=0.0178 V`