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A hydrogen electrode placed in a solutio...

A hydrogen electrode placed in a solution containing sodium acetate and acetic acid in the ratio of `x:y` and `y:x` has an electrode potential value `E_(1)` and `E_(2)` volts, respectively, at `25^(@)C`. The `pK_(a)` value of acetic acid is

A

`(-(E_(1)+E_(2)))/(2xx0.059)`

B

`(E_(1)+E_(2))/(2xx0.059)`

C

`(E_(2)-E_(1))/(2xx0.059)`

D

`(-(E_(1)+E_(1)))/(0.059)`

Text Solution

Verified by Experts

The correct Answer is:
a

`Pt|H_(2)|"Sodium acetate"+CH_(3)COOH(x:y)`
`pH` of acidic buffer `=pK_(a)+log((Sal t)/(Aci d))`
`:. pH_(1)=pK_(a)+log.(y)/(x)`
`:. E_(1)=-0.059pH_(1)`
`E_(2)=-0.059pH_(2)`
`(E_(1)+E_(2))=-0.059(pK_(a)+log.(y)/(y))-0.059(pK_(a)+log.(y)/(x))`
Solve `pK_(a)=(-(E_(1)+E_(2)))/(2xx0.059)`
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A hydrogen electrode X was placed in a buffer solution of sodium acetate ad acetic acid in the ratio a:b and another hydrogen electrode Y was placed in a buffer solution of sodium acetate ad acetic in the ratio b:a if reduction potential values for two cells are found to be E_(1) and E_(2) respectively w.r.t. standard hydrogen electrode, the pK_(a) value of the acid can be given as (A) (E_(1)-E_(2))/(0.118) (B). -(E_(1)+E_(2))/(0.118) (C). (E_(1))/(E_(2))xx0.118 (D). (E_(2)-E_(1))/(0.118)

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