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Pt(H(2))(1atm)|H(2)O, electrode potentia...

`Pt(H_(2))(1atm)|H_(2)O`, electrode potential at `298K` is

A

`-0.2364V`

B

`-0.4137V`

C

`0.4137V`

D

`0.00V`

Text Solution

Verified by Experts

The correct Answer is:
c
Since oxidation occurs.
`H_(2) rarr 2H^(o+)+2e^(-)`
`Q=[H^(o+)]^(2)=10^(-14)M^(2) i n H_(2)O`
` E=E^(c-)-(0.0591)/(2)log10^(-14)`
`=0+0.0.591xx7=0.4137V`
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