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Calculate E^(c-) for the reactions : Z...

Calculate `E^(c-)` for the reactions `:`
`ZnY^(2-)hArrZn(s)+Y^(4-)` where `Y^(4-)` is the completely deprotonated anion of EDTA. The formation constant for`ZnY^(2-)` is `3.2xx10^(16)` and `E^(c-)` for `Zn rarr Zn^(2+)+2e^(-)` is `0.76V`.

A

`-1.25V`

B

`0.48V`

C

`+0.68V`

D

`-0.27V`

Text Solution

Verified by Experts

The correct Answer is:
a
`E^(c-)._(Zn^(2+)|ZnY^(2-)|Y^(4-))=-E^(c-)._(Zn^(2+)|Zn)+(0.059)/(2)logK`
`K_(f)=([ZnY^(2-)])/([Y^(4-)])impliesK=(1)/(K_(f))`
`E^(c-)._(Zn^(2+)|ZnY^(2-)|Y^(4-))`
`=-0.76+(0.059)/(2)log.(1)/(3.2xx10^(16))=-1.25V`
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