`k=4.95xx10^(-5) S cm^(-1)` for a `0.001 M `solution. The reciprocal of the degree of dissociation of acetic acid, if `wedge_(m)^(@)` for acetic acid is `400S cm^(-2) mol^(-1)` is `:`

Options

A. 7
B. 8
C. 9
D. 10

Answer

b

Explanation

`k=4.95xx10^(-5)S cm^(-1), alpha=(wedge_(m))/(wedge^(@)._(m))`
`wedge_(m)=1000xx(k)/(C)=1000xx(4.95xx10^(-5))/(0.001)=49.5 S cm^(-1)`
`impliesalpha=(49.5)/(400)implies (1)/(alpha)=(400)/(49.5)~~8`