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What is the value of pK(b)(CH(3)COO^(c-)...

What is the value of `pK_(b)(CH_(3)COO^(c-))` if `wedge^(@)._(m)=390 S cm^(-1) mol ^(-1)` and `wedge_(m)=7.8 S cm^(2) mol^(-1)` for `0.04 M` of `CH_(3)COOH` at `25^(@)C`?

A

`9.3`

B

`9.2`

C

`4.7`

D

`4.8`

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The correct Answer is:
To find the value of \( pK_b \) for the acetate ion \( CH_3COO^- \), we will follow these steps: ### Step 1: Calculate the degree of dissociation (\( \alpha \)) Given: - Molar conductivity of acetate ion, \( \Lambda_m = 390 \, \text{S cm}^2 \text{mol}^{-1} \) - Conductivity of acetic acid solution, \( \kappa = 7.8 \, \text{S cm}^{-1} \) - Concentration of acetic acid, \( C = 0.04 \, \text{M} \) The degree of dissociation \( \alpha \) can be calculated using the formula: \[ \alpha = \frac{\kappa}{\Lambda_m} \] Substituting the values: \[ \alpha = \frac{7.8 \, \text{S cm}^{-1}}{390 \, \text{S cm}^2 \text{mol}^{-1}} = 0.02 \] ### Step 2: Calculate the dissociation constant (\( K_a \)) The dissociation of acetic acid can be represented as: \[ CH_3COOH \rightleftharpoons H^+ + CH_3COO^- \] The equilibrium expression for the dissociation constant \( K_a \) is given by: \[ K_a = \frac{[H^+][CH_3COO^-]}{[CH_3COOH]} \] At equilibrium: - Initial concentration of \( CH_3COOH = C = 0.04 \, \text{M} \) - Change in concentration due to dissociation = \( C \alpha = 0.04 \times 0.02 = 0.0008 \, \text{M} \) Thus, at equilibrium: - \( [H^+] = C \alpha = 0.0008 \, \text{M} \) - \( [CH_3COO^-] = C \alpha = 0.0008 \, \text{M} \) - \( [CH_3COOH] = C - C \alpha = 0.04 - 0.0008 = 0.0392 \, \text{M} \) Now substituting these values into the expression for \( K_a \): \[ K_a = \frac{(0.0008)(0.0008)}{0.0392} = \frac{6.4 \times 10^{-7}}{0.0392} \approx 1.63 \times 10^{-5} \] ### Step 3: Calculate \( pK_a \) Using the formula: \[ pK_a = -\log K_a \] Substituting the value of \( K_a \): \[ pK_a = -\log(1.63 \times 10^{-5}) \approx 4.79 \] ### Step 4: Calculate \( pK_b \) Using the relationship: \[ pK_a + pK_b = 14 \] We can find \( pK_b \): \[ pK_b = 14 - pK_a = 14 - 4.79 \approx 9.21 \] ### Final Answer The value of \( pK_b \) for the acetate ion \( CH_3COO^- \) is approximately **9.21**. ---

To find the value of \( pK_b \) for the acetate ion \( CH_3COO^- \), we will follow these steps: ### Step 1: Calculate the degree of dissociation (\( \alpha \)) Given: - Molar conductivity of acetate ion, \( \Lambda_m = 390 \, \text{S cm}^2 \text{mol}^{-1} \) - Conductivity of acetic acid solution, \( \kappa = 7.8 \, \text{S cm}^{-1} \) - Concentration of acetic acid, \( C = 0.04 \, \text{M} \) ...
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