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Number of Faradays required to reduce 3 ...

Number of Faradays required to reduce `3 mol` of `MnO_(4)^(c-)` to `MnO^(2+)` is `……………………….F`

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The correct Answer is:
`(15F)`
`(15F)`
`8H^(o+)+5e^(-) +MnO_(4)^(c-) rarr Mn^(2+)+4H_(2)O `
`1 mol` of `MnO_(4)^(c-) -=5e^(-)=5F`.
`3 mol `of `MnO_(4)^(C-)=5xx3=15F`
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