The `EMF` of the cell `:`
`Pt, H_(2)(1atm)|H^(o+)(aq)||AgCl|Ag` is `0.27` and `0.26V` at `25^(@)C`, respectively. The heat of the reaction occuring inside the cell at `25^(@)C` is `………………….. kJ K^(-1)`

Answer

`(-54.8kJ K^(-1))`

Explanation

`(-54.9k J K^(-1))`
`((delE)/(delT))_(P)=((0.26-0.27)/(35-25))=(-0.01)/(10)V K^(-1)[n_(cell)=1]`
`DeltaH=-nF[E_(cell)(at 25^(@)C)-T((delE)/(delT))_(P)]`
`DeltaH=-1xx96500[0.27-298(-(0.01)/(10))]`
`DeltaH=-1xx96500Cxx0.568V K^(-1)=-54812 J K^(-1)`
`=-54.8 k J K^(-1)`